How do i use regex_findall filter to display partial output of 'sh clock' command?

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1

In below output, i want only the ‘May 11 2021’ to be displayed on screen.
Switch#sh clock
02:42:19.622 Sng Tue May 11 2021

Below is a sample script and used ‘regex’ filter as an example. How do i modify the script/ incorporate other any other filter such that my above objective is achieved?

  • name: GATHER SHOW VERSION
    ios_command:
    commands: “show clock”

register: show_clock

  • debug:
    msg:
  • “{{ show_clock.stdout[0] | regex_findall('…)”

Thanks,
Vikram

2

something like - “{{ show_clock.stdout[0] | regex_findall(‘[A-Z][a-z]{2}\s[0-9]{2}\s[0-9]{4}’)” should work although I am no expert so there may be a better way to do it.

I found https://regexone.com/ to be helpful to learn the basics and https://regex101.com/ for testing.

3

Hi,

I suspect your script may show ewverything in ‘sh clock’ output and not the partial output i wanted. Thanks for the links, will check them.

Regards,
Vikram

4

You expect this based on? First check.

If you must parse dates like that, it requires more data. Is the first
line ('Switch#sh clock') also part of the output? Let's assume so.
And is the month abbreviated or not? From just 'May' we can't tell.
Assuming it is, this works, in this century:

"{{ out | regex_replace(
          '(?s).*(Mon|Tue|Wed|Thu|Fri|Sat|Sun)\\s+(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)\\s+(\\d{1,2})\\s+(20\\d\\d)$',
          '\\2 \\3 \\4'
          ) }}"