Conditional Variable Prompt using when

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1

According to http://docs.ansible.com/ansible/playbooks_variables.html

" the when conditional can also be used with variables"

However here is my issue with it on ansible-1.9.2-1.

I’m setting a vars_prompt for version number.
When running through it, i’m specifying Version 11.

`

  • name: “version_no”
    prompt: “What version of oracle are we setting? 11 or 12. 11 is default”
    default: “11”
    private: no
    `

Then an associated variable called lib_dir_version based on the version entered.

`
vars:

lib_dir_version: “11.2”
when: “{{version_no}} == 11”

lib_dir_version: “12.1”
when: “{{version_no}} == 12”
`

However the above always only takes 12.1 as the return when i Echo Out.

`
tasks:

  • name: “Echo dir version”
    shell: echo “My lib dir version is {{ lib_dir_version }}.”
    `

FROM messages on host.

args=echo "My lib dir version is 12.1." removes=None NO_LOG=None shell=True warn=True

Why cant i figure this out?

Whats wrong with my syntax?

Chris

2

you are misunderstanding the docs, the use of variables IN the
conditional 'when' not using when to make var assignment conditional,
for that you can use filters:

vars:
   lib_dir_version: "{{ version_no == 12|ternary(12, 11) }}"

3

Thanks for the response Brian

So far I have changed the syntax to the following: (Had to wrap the version_no == 12 in ( ) to supress False passing through.

lib_dir_version: "{{ (version_no == 12)| ternary('12','11') }}"

If I enter 11 in my prompt - I get the expected echo of

echo "My lib dir version is 11."

However when I rerun the playbook, and specify 12 as the version number in my prompt, I still get Version 11 in the output.

echo "My lib dir version is 11."

Kind Regards
Chris

4

This seems to have sorted it!

lib_dir_version: "{{ (version_no == '12')|ternary('12','11') }}"

single quoted the value ‘12’

Brian Thanks for the heads up - Pointed me properly in the right direction

Thank you!
Chris