Ansible variable with find

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1

Running the playbook below and wondering whats the correct syntax so I can use a variable within the find statement below

This line is in question -
when: p.stdout.find"{{(‘user’)}}" != -1

This would be correct without a variable

when: p.stdout.find(‘daniel’) != -1

How do I do this with a variable?

Playbook

  • hosts: localhost
    become: yes
    vars:
    user: daniel
    tasks:
  • name: Create a new user on the server
    user:
    name: “{{user}}”
    state: present
  • name: Check to ensure the user has been created
    shell: cat /etc/passwd | grep “{{user}}”
    register: p
  • debug: msg=“The user {{user}} exists”
    when: p.stdout.find"{{(‘user’)}}" != -1
  • name: Create a file in the /opt folder called program1.sh
    command: touch program1.sh
    args:
    chdir: /opt
    creates: program1.sh
2

when: p.stdout.find(user) != -1

3

Thanks! But how does it differentiate between just the text user, and the actual variable user? Or does it just know because user is defined as a variable at the top in the vars section?

I tried that out and it works well.

4

Text is indicated with single or double quote, so 'user' or "user".
When you don't use quotes it's taken as the variable user.

5

Great explanation. Thanks