# Replace host name in yml file **URL:** \ **Category:** Ansible Project\ **Created:** [August 10, 2016, 5:43pm UTC](https://forum.ansible.com/t/replace-host-name-in-yml-file/22267 "2016-08-10T17:43:59Z")\ **Posts on this page:** 3\ **Page:** 1
**Author:** ![Anushri\_Mishra](https://avatars.discourse-cdn.com/v4/letter/a/65b543/32.png) [@Anushri\_Mishra](https://forum.ansible.com/u/Anushri_Mishra)\ **Post date:** [August 10, 2016, 5:43pm UTC](https://forum.ansible.com/t/replace-host-name-in-yml-file/22267/1 "2016-08-10T17:43:59Z")
hi I have a question this is my main.yml file content: - name: Start Tomcat # service: name=tomcat7 state=restarted enabled=yes command: wget “[http://admin](http://admin):admin@ **10.1.33.155** :8080/manager/text/stop?path=/externaluserwebapi” -O - -q become: True become\_method: sudo run\_once: true changed\_when: False Now as you can see there is server name in the command itself (bolded) and it is basically stopping a given application running in tomcat server vs the whole server. Now my problem is that how can i run this for the given hosts file. Is there a way I can replace the hardcoded server name here by hosts from the hosts file? Please advise. Thanks. ---
**Author:** ![Dick\_Davies](https://avatars.discourse-cdn.com/v4/letter/d/b9e5f3/32.png) [@Dick\_Davies](https://forum.ansible.com/u/Dick_Davies)\ **Post date:** [August 10, 2016, 6:40pm UTC](https://forum.ansible.com/t/replace-host-name-in-yml-file/22267/2 "2016-08-10T18:40:47Z")
That command is going to run on the tomcat server, so you probably can just use 127.0.0.1 ---
**Author:** ![Anushri\_Mishra](https://avatars.discourse-cdn.com/v4/letter/a/65b543/32.png) [@Anushri\_Mishra](https://forum.ansible.com/u/Anushri_Mishra)\ **Post date:** [August 10, 2016, 6:51pm UTC](https://forum.ansible.com/t/replace-host-name-in-yml-file/22267/3 "2016-08-10T18:51:53Z")
omg never thought of that 🙂 thanks !!